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0=5n^2-n-238
We move all terms to the left:
0-(5n^2-n-238)=0
We add all the numbers together, and all the variables
-(5n^2-n-238)=0
We get rid of parentheses
-5n^2+n+238=0
a = -5; b = 1; c = +238;
Δ = b2-4ac
Δ = 12-4·(-5)·238
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4761}=69$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-69}{2*-5}=\frac{-70}{-10} =+7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+69}{2*-5}=\frac{68}{-10} =-6+4/5 $
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